Explorer
SQL

Find users who logged in on at least 2 consecutive days.

Problem Statement

<p>Find <code>users</code> who logged in on at least 2 consecutive days.</p>

Examples

Input: logins table: +---------+------------+ | user_id | login_date | +---------+------------+ | 1 | 2024-01-01 | | 1 | 2024-01-02 | | 1 | 2024-01-04 | | 2 | 2024-01-05 | | 2 | 2024-01-06 | | 2 | 2024-01-07 | | 3 | 2024-01-10 | +---------+------------+

Output: +---------+ | user_id | +---------+ | 1 | | 2 | +---------+

Explanation: The query retrieves the requested records satisfying all problem requirements.

Complexity

Time Complexity: -

Space Complexity: -

Hints

šŸ’” Hint 1: Determine which tables contain the required columns and relate them using INNER JOIN on the corresponding foreign/primary keys. šŸ’” Hint 2: Write out the ON condition matching key fields (e.g. ON a.key = b.key) and apply any filtering in the WHERE clause. šŸ’” Hint 3: Select only the requested columns in the SELECT clause with clear aliases if needed: SELECT ... FROM ... INNER JOIN ... ON ...;

Editorial & Approach

Problem Overview & Intuition

To solve "Consecutive Days Detection", we query the relational database engine using declarative SQL. The goal is to find users who logged in on at least 2 consecutive days. By formulating an optimal execution plan with appropriate projection and filtering, the database engine executes the query with minimal overhead.

Step-by-Step Approach

  1. Analyze Schema: Identify the target tables, necessary foreign keys, and expected output columns.
  2. Construct Filtering & Logic: Apply table joins to isolate the requested data.
  3. Format & Order: Ensure columns match the expected project schema in order.

Optimal Implementation (SQL)

SELECT DISTINCT l1.user_id FROM logins l1 JOIN logins l2 ON l1.user_id = l2.user_id AND l1.login_date = l2.login_date - INTERVAL '1 day';

Complexity Analysis

Time Complexity O(N * M) worst-case, O(N + M) with hash/merge join on indexed keys.
Space Complexity O(N) for join buffer and result set.

Key Considerations & Edge Cases

  • Empty Tables: The query executes safely returning zero rows without syntax error.
  • NULL Values: Columns containing NULL values are properly handled by standard ANSI SQL semantics.
  • Case Sensitivity: String comparisons and keywords adhere to PostgreSQL/standard SQL rules.

Consecutive Days Detection

Hard

Find users who logged in on at least 2 consecutive days.

Example Scenarios
1Example 1
Input:
logins table
user_idlogin_date
12024-01-01
12024-01-02
12024-01-04
22024-01-05
22024-01-06
22024-01-07
32024-01-10
Output:
user_id
1
2
Explanation:

The query retrieves the requested records satisfying all problem requirements.

SQL Editor
Loading Editor...
Query Results

Run a query to see results here.