Select name, and a "type" column that is "Senior" if age > 35 else "Junior".
Problem Statement
Examples
Input: users table: +----+-------+-----+ | id | name | age | +----+-------+-----+ | 1 | Alice | 30 | | 2 | Bob | 40 | +----+-------+-----+
Output: +-------+--------+ | name | type | +-------+--------+ | Alice | Junior | | Bob | Senior | +-------+--------+
Explanation: The query retrieves the requested records satisfying all problem requirements.
Complexity
Time Complexity: -
Space Complexity: -
Hints
Editorial & Approach
Problem Overview & Intuition
To solve "Basic CASE Statement", we query the relational database engine using declarative SQL. The goal is to select name, and a "type" column that is "senior" if age > 35 else "junior". By formulating an optimal execution plan with appropriate projection and filtering, the database engine executes the query with minimal overhead.
Step-by-Step Approach
- Analyze Schema: Identify the target tables, necessary foreign keys, and expected output columns.
- Construct Filtering & Logic: Apply row projections to isolate the requested data.
- Format & Order: Ensure columns match the expected project schema in order.
Optimal Implementation (SQL)
SELECT name, CASE WHEN age > 35 THEN 'Senior' ELSE 'Junior' END AS type FROM users;
Complexity Analysis
Key Considerations & Edge Cases
- Empty Tables: The query executes safely returning zero rows without syntax error.
- NULL Values: Columns containing NULL values are properly handled by standard ANSI SQL semantics.
- Case Sensitivity: String comparisons and keywords adhere to PostgreSQL/standard SQL rules.