Get user name and their total amount ordered.
Problem Statement
Examples
Input: users table: +----+-------+ | id | name | +----+-------+ | 1 | Alice | | 2 | Bob | +----+-------+ orders table: +-----+---------+-------+ | id | user_id | total | +-----+---------+-------+ | 101 | 1 | 50 | | 102 | 1 | 30 | | 103 | 2 | 100 | +-----+---------+-------+
Output: +-------+---------------+ | name | total_ordered | +-------+---------------+ | Alice | 80 | | Bob | 100 | +-------+---------------+
Explanation: The query joins the matching records on the related keys and projects the requested fields.
Complexity
Time Complexity: -
Space Complexity: -
Hints
Editorial & Approach
Problem Overview & Intuition
To solve "Aggregate with Join", we query the relational database engine using declarative SQL. The goal is to get user name and their total amount ordered. By formulating an optimal execution plan with appropriate projection and filtering, the database engine executes the query with minimal overhead.
Step-by-Step Approach
- Analyze Schema: Identify the target tables, necessary foreign keys, and expected output columns.
- Construct Filtering & Logic: Apply table joins to isolate the requested data.
- Format & Order: Ensure columns match the expected project schema in order.
Optimal Implementation (SQL)
SELECT users.name, SUM(orders.total) AS total_ordered FROM users JOIN orders ON users.id = orders.user_id GROUP BY users.name;
Complexity Analysis
Key Considerations & Edge Cases
- Empty Tables: The query executes safely returning zero rows without syntax error.
- NULL Values: Columns containing NULL values are properly handled by standard ANSI SQL semantics.
- Case Sensitivity: String comparisons and keywords adhere to PostgreSQL/standard SQL rules.