Write a function `processEmployees(employees)` that filters employees with salary > 50000, maps them to just their names, and sorts alphabetically.

💡 Hint 1: Chain .filter().map().sort() for a pipeline approach. 💡 Hint 2: Filter by salary, map to name, sort with localeCompare or default. 💡 Hint 3: return employees.filter(e => e.salary > 50000).map(e => e.name).sort(); ✅ Solution: ```javascript function processEmployees(employees) { return employees.filter(e => e.salary > 50000).map(e => e.name).sort(); } ```