Explorer
MongoDB

Delete all expired coupons (`expired: true`), insert a new coupon `{ _id: 10, code: "NEW50", expired: false }`, and return the total count of coupons.

Problem Statement

<p>Delete all expired coupons (<code>expired: true</code>), insert a new coupon <code>{ <code>_id</code>: 10, code: "NEW50", expired: false }</code>, and return the total count of coupons.</p>

Examples

Input: coupons collection: +-----+--------+---------+ | _id | code | expired | +-----+--------+---------+ | 1 | SAVE10 | true | | 2 | SAVE20 | false | | 3 | SAVE30 | true | | 4 | SAVE40 | false | +-----+--------+---------+

Output: +-------+ | count | +-------+ | 3 | +-------+

Explanation: The query calculates the total count of documents that satisfy the given filter criteria.

Complexity

Time Complexity: -

Space Complexity: -

Hints

šŸ’” Hint 1: Use db.<collection>.find(<filter>) to query the documents in the collection. šŸ’” Hint 2: Pass an empty object {} to retrieve all documents, or specify key-value pairs for exact matching. šŸ’” Hint 3: Chain .toArray() to resolve the MongoDB cursor into a JavaScript array: return db.<collection>.find(...).toArray();

Editorial & Approach

Problem Overview & Intuition

To solve "Multi-Step: Delete + Insert + Count", we query the MongoDB document store. The goal is to delete all expired coupons (`expired: true`), insert a new coupon `{ _id: 10, code: "new50", expired: false }`, and return the total count of coupons. Using a targeted find query, the database engine filters and structures the BSON documents efficiently.

Step-by-Step Approach

  1. Identify Target Collection: Access the collection through the db instance.
  2. Construct Query / Pipeline: Build the query filter with appropriate comparison operators.
  3. Resolve Cursor: Invoke .toArray() to transform the query cursor into the required array of documents.

Optimal Implementation (MongoDB)

function solve(db) {
  db.coupons.deleteMany({ expired: true });
  db.coupons.insertOne({ _id: 10, code: "NEW50", expired: false });
  return db.coupons.countDocuments({});
}

Complexity Analysis

Time Complexity O(N) collection scan (O(log N) if index is present on filtered fields).
Space Complexity O(K) where K is the number of returned documents in memory.

Key Considerations & Edge Cases

  • Empty Collections: If no documents match, the query cleanly returns an empty array [].
  • Missing / NULL Fields: Missing fields in documents are handled safely without throwing runtime exceptions.
  • Type Coercion: BSON types (ObjectId, Numbers, Strings) are compared strictly according to MongoDB specifications.

Multi-Step: Delete + Insert + Count

Medium

Delete all expired coupons (expired: true), insert a new coupon { _id: 10, code: "NEW50", expired: false }, and return the total count of coupons.

Example Scenarios
1Example 1
Input:
coupons collection
_idcodeexpired
1SAVE10true
2SAVE20false
3SAVE30true
4SAVE40false
Output:
count
3
Explanation:

The query calculates the total count of documents that satisfy the given filter criteria.

MongoDB Editor
Loading Editor...
Query Results (JSON)

Run your MongoDB code to see results here.