Delete all expired coupons (`expired: true`), insert a new coupon `{ _id: 10, code: "NEW50", expired: false }`, and return the total count of coupons.
Problem Statement
Examples
Input: coupons collection: +-----+--------+---------+ | _id | code | expired | +-----+--------+---------+ | 1 | SAVE10 | true | | 2 | SAVE20 | false | | 3 | SAVE30 | true | | 4 | SAVE40 | false | +-----+--------+---------+
Output: +-------+ | count | +-------+ | 3 | +-------+
Explanation: The query calculates the total count of documents that satisfy the given filter criteria.
Complexity
Time Complexity: -
Space Complexity: -
Hints
Editorial & Approach
Problem Overview & Intuition
To solve "Multi-Step: Delete + Insert + Count", we query the MongoDB document store. The goal is to delete all expired coupons (`expired: true`), insert a new coupon `{ _id: 10, code: "new50", expired: false }`, and return the total count of coupons. Using a targeted find query, the database engine filters and structures the BSON documents efficiently.
Step-by-Step Approach
- Identify Target Collection: Access the collection through the
dbinstance. - Construct Query / Pipeline: Build the query filter with appropriate comparison operators.
- Resolve Cursor: Invoke
.toArray()to transform the query cursor into the required array of documents.
Optimal Implementation (MongoDB)
function solve(db) {
db.coupons.deleteMany({ expired: true });
db.coupons.insertOne({ _id: 10, code: "NEW50", expired: false });
return db.coupons.countDocuments({});
}
Complexity Analysis
Key Considerations & Edge Cases
- Empty Collections: If no documents match, the query cleanly returns an empty array
[]. - Missing / NULL Fields: Missing fields in documents are handled safely without throwing runtime exceptions.
- Type Coercion: BSON types (ObjectId, Numbers, Strings) are compared strictly according to MongoDB specifications.