Count patients per `department`, sort by count descending, and project `_id` as `department` and show `patientCount`.
Problem Statement
Examples
Input: patients collection: +-----+------+------------+ | _id | name | department | +-----+------+------------+ | 1 | A | Cardiology | | 2 | B | Neurology | | 3 | C | Cardiology | | 4 | D | Cardiology | | 5 | E | Neurology | +-----+------+------------+
Output: +--------------+ | patientCount | +--------------+ | 3 | | 2 | +--------------+
Explanation: The query calculates the total count of documents that satisfy the given filter criteria.
Complexity
Time Complexity: -
Space Complexity: -
Hints
Editorial & Approach
Problem Overview & Intuition
To solve "Hospital: Count Patients Per Department", we query the MongoDB document store. The goal is to count patients per `department`, sort by count descending, and project `_id` as `department` and show `patientcount`. Using an aggregation pipeline, the database engine filters and structures the BSON documents efficiently.
Step-by-Step Approach
- Identify Target Collection: Access the collection through the
dbinstance. - Construct Query / Pipeline: Build the aggregation stages ($match, $group, $sort, etc.).
- Resolve Cursor: Invoke
.toArray()to transform the query cursor into the required array of documents.
Optimal Implementation (MongoDB)
function solve(db) {
return db.patients.aggregate([
{ $group: { _id: "$department", patientCount: { $sum: 1 } } },
{ $sort: { patientCount: -1 } },
{ $project: { _id: 0, department: 1, patientCount: 1 } }
]);
}
Complexity Analysis
Key Considerations & Edge Cases
- Empty Collections: If no documents match, the query cleanly returns an empty array
[]. - Missing / NULL Fields: Missing fields in documents are handled safely without throwing runtime exceptions.
- Type Coercion: BSON types (ObjectId, Numbers, Strings) are compared strictly according to MongoDB specifications.