Get all distinct `city` values from orders where `amount` is greater than `100`.
Problem Statement
Examples
Input: orders collection: +-----+---------+--------+ | _id | city | amount | +-----+---------+--------+ | 1 | NYC | 150 | | 2 | LA | 50 | | 3 | NYC | 200 | | 4 | Chicago | 300 | | 5 | LA | 120 | +-----+---------+--------+
Output: +---------+ | result | +---------+ | NYC | | Chicago | | LA | +---------+
Explanation: The target document is modified according to the update operators and the updated document is returned.
Complexity
Time Complexity: -
Space Complexity: -
Hints
Editorial & Approach
Problem Overview & Intuition
To solve "Distinct with Filter", we query the MongoDB document store. The goal is to get all distinct `city` values from orders where `amount` is greater than `100`. Using a targeted find query, the database engine filters and structures the BSON documents efficiently.
Step-by-Step Approach
- Identify Target Collection: Access the collection through the
dbinstance. - Construct Query / Pipeline: Build the query filter with appropriate comparison operators.
- Resolve Cursor: Invoke
.toArray()to transform the query cursor into the required array of documents.
Optimal Implementation (MongoDB)
function solve(db) {
return db.orders.distinct("city", { amount: { $gt: 100 } });
}
Complexity Analysis
Key Considerations & Edge Cases
- Empty Collections: If no documents match, the query cleanly returns an empty array
[]. - Missing / NULL Fields: Missing fields in documents are handled safely without throwing runtime exceptions.
- Type Coercion: BSON types (ObjectId, Numbers, Strings) are compared strictly according to MongoDB specifications.